Question:

For a sparingly soluble salt ApBq, the relationship of its solubility product Kₛp with its solubility S is:

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For a salt ApBq: Kₛp=(pS)ᵖ(qS)q Always raise concentrations to their stoichiometric powers.
Updated On: Mar 19, 2026
  • \(K_{sp}=S^p(p)^p\,S^q(q)^q\)
  • \(K_{sp}=Sp+q\)
  • \(K_{sp}=Sp+q\,p^q\)
  • Kₛp=Sᵖpᵖ qq
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The Correct Option is A

Solution and Explanation


Step 1:
Dissociation of salt: ApBq(s)rightleftharpoons pAq++qBᵖ-
Step 2:
If solubility is S: [Aq+]=pS, [Bᵖ-]=qS
Step 3:
Solubility product: Kₛp=(pS)ᵖ(qS)q
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