1.0MKCl with Pt electrodes.
If volume of electrolytic solution is maintained constant in each of the cell, which is correct set of pH changes in (A), (B) and (C) cell respectively?
decrease in all the three
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The Correct Option isC
Solution and Explanation
Cell (A): Pt electrodes in CuSO₄.
Cathode: Cu²++2e⁻ → Cu
Anode: 2H₂O → O₂ + 4H⁺ + 4e⁻
⟹ H⁺ increases, pH decreases.
Cell (B): Cu electrodes in CuSO₄.
Cathode: Cu²++2e⁻ → Cu
Anode: Cu → Cu²++2e⁻
⟹ No change in H⁺, pH constant.
Cell (C): Pt electrodes in KCl.
Cathode: 2H₂O+2e⁻ → H₂+2OH⁻
Anode: 2Cl⁻ → Cl₂+2e⁻
⟹ OH⁻ increases, pH increases.