Question:
In group 14 elements, element X has lowest melting point. This on heating with steam gives a compound Y. What is Y?
In group 14 elements, element X has lowest melting point. This on heating with steam gives a compound Y. What is Y?
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Unlike Tin, Lead (Pb) does not react with steam easily because of the rapid formation of a protective oxide layer on its surface.
Tin reacts completely to form $\text{SnO}_2$.
Tin reacts completely to form $\text{SnO}_2$.
Updated On: Jul 22, 2026
- $\text{CO}_2$
- $\text{SiO}_2$
- $\text{GeO}_2$
- $\text{SnO}_2$
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Question:
First, we must identify the Group 14 element X that possesses the lowest melting point.
Then, we determine the product Y when this element X reacts with steam.
Step 2: Key Formula or Approach:
Let us examine the elements of Group 14: Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb).
We review their physical properties (melting points) and chemical reactivity with steam.
Step 3: Detailed Explanation:
• Let us look at the melting points of Group 14 elements:
Carbon: sublimes around $4000\text{ K}$.
Silicon: $1687\text{ K}$.
Germanium: $1211\text{ K}$.
Tin (Sn): $505\text{ K}$ (lowest).
Lead (Pb): $601\text{ K}$.
Therefore, the element X with the lowest melting point is Tin (Sn).
• Reaction of Tin with steam:
Tin is stable in cold water but reacts with steam at red heat to form tin dioxide ($\text{SnO}_2$) and dihydrogen:
\[ \text{Sn} + 2\text{H}_2\text{O}(steam) \xrightarrow{\Delta} \text{SnO}_2 + 2\text{H}_2 \]
• Thus, the compound Y formed is $\text{SnO}_2$.
Step 4: Final Answer:
The compound Y is $\text{SnO}_2$.
First, we must identify the Group 14 element X that possesses the lowest melting point.
Then, we determine the product Y when this element X reacts with steam.
Step 2: Key Formula or Approach:
Let us examine the elements of Group 14: Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb).
We review their physical properties (melting points) and chemical reactivity with steam.
Step 3: Detailed Explanation:
• Let us look at the melting points of Group 14 elements:
Carbon: sublimes around $4000\text{ K}$.
Silicon: $1687\text{ K}$.
Germanium: $1211\text{ K}$.
Tin (Sn): $505\text{ K}$ (lowest).
Lead (Pb): $601\text{ K}$.
Therefore, the element X with the lowest melting point is Tin (Sn).
• Reaction of Tin with steam:
Tin is stable in cold water but reacts with steam at red heat to form tin dioxide ($\text{SnO}_2$) and dihydrogen:
\[ \text{Sn} + 2\text{H}_2\text{O}(steam) \xrightarrow{\Delta} \text{SnO}_2 + 2\text{H}_2 \]
• Thus, the compound Y formed is $\text{SnO}_2$.
Step 4: Final Answer:
The compound Y is $\text{SnO}_2$.
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