A \(1.0\ L\) aqueous solution contains \(1\times 10^{-8}\ M\ NaBr\), \(1\times 10^{-8}\ M\ NaCl\) and \(1\times 10^{-8}\ M\ NaI\). To this solution, \(1\times 10^{-10}\ M\) aqueous \(AgNO_3\) solution is added drop wise. The order of precipitation of \(AgX\), where \(X=Cl, Br, I\), is
\[
K_{sp}(AgCl)=1.8\times 10^{-10}
\]
\[
K_{sp}(AgBr)=5\times 10^{-13}
\]
\[
K_{sp}(AgI)=8.3\times 10^{-17}
\]