Question:

Work function = 1.8 eV. KE max = 2.2 eV. Frequency is doubled. Find new KE max.

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Photoelectric effect depends linearly on frequency.
Updated On: Jun 17, 2026
  • 7.2 eV
  • 6.2 eV
  • 4.4 eV
  • 3.6 eV
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The Correct Option is B

Solution and Explanation


Step 1: Photoelectric equation: \[ K_{\max} = h\nu - \phi \]
Step 2: Initially: \[ 2.2 = h\nu - 1.8 \Rightarrow h\nu = 4.0\ \text{eV} \]
Step 3: Frequency doubled: \[ h\nu' = 8.0\ \text{eV} \]
Step 4: \[ K'_{\max} = 8.0 - 1.8 = 6.2\ \text{eV} \]
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