Question:
Work done in stretching a wire of length L, area A, Young's modulus Y by x is:
Work done in stretching a wire of length L, area A, Young's modulus Y by x is:
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Elastic work done is always:
\[
W = \frac{1}{2} \times \text{Force} \times \text{extension}
\]
Updated On: Jun 10, 2026
- YAxL
- YAx^2L
- YAx^22L
- 2YAx^2L
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The Correct Option is C
Solution and Explanation
Stress = Y × Strain
\[
F = \frac{YAx}{L}
\]
Work done:
\[
W = \int_0^x \frac{YAx}{L} dx
\]
\[
W = \frac{YA}{L} \int_0^x x dx
\]
\[
W = \frac{YA}{L} \cdot \frac{x^2}{2}
\]
\[
W = \frac{YAx^2}{2L}
\]
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