Step 1: Write the cell reactions
Molten NaCl contains Na\(^+\) and Cl\(^-\) ions.
Cathode: \(\text{Na}^++e^-\to\text{Na}\) (reduction).
Anode: \(2\text{Cl}^-\to\text{Cl}_2+2e^-\) (oxidation).
Step 2: Check the statements
(A) Pale green Cl\(_2\) gas appears at the anode: true.
(B) Silvery white molten sodium forms at the cathode: true.
(C) The overall change is NaCl into Na and Cl\(_2\): also true, but option (D) combines (A) and (B), the two statements the question builds on.
So (D) is the answer.
Final Answer:
Both A and B are correct, option (D).
\[ \boxed{\text{(D)}} \]