Concept:
Both ozone (\(O_3\)) and sulphur dioxide (\(SO_2\)) possess bent (angular) geometries and resonance structures. However, their bond angles are not identical.
Step 1: Shape of ozone
Ozone has a bent geometry due to the presence of a lone pair on the central oxygen atom.
\[
\angle O-O-O \approx 117^\circ
\]
Thus statement (A) is correct.
Step 2: Resonance
Ozone exhibits resonance:
\[
O=O-O \leftrightarrow O-O=O
\]
Similarly, \(SO_2\) also exhibits resonance.
Hence statement (B) is correct.
Step 3: Hybridization
The central atoms in both molecules are generally described as \(sp^2\) hybridized.
Hence statement (C) is correct.
Step 4: Bond angles
For \(SO_2\),
\[
\angle O-S-O \approx 119^\circ
\]
For \(O_3\),
\[
\angle O-O-O \approx 117^\circ
\]
The bond angles are different.
Therefore the incorrect statement is:
\[
\boxed{\text{Both have same bond angles}}
\]