All natural radioactive processes follow first order kinetics.
Thermal decomposition of HI on gold surface is a zero-order reaction.
Decomposition of hydrogen peroxide catalysed by iodide in an alkaline medium is a first order reaction.
The unit of second order rate constant is mol$^{-1}$L s$^{-1}$.
The experimental rate expression of the reaction CHCl$_3$ + Cl$_2 \rightarrow$ CCl$_4$ + HCl is, Rate $=k[$CHCl$_3][$Cl$_2]$
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The Correct Option is
Solution and Explanation
Concept:
The rate law of a reaction is determined experimentally. It cannot be predicted only from stoichiometric coefficients unless the reaction is elementary.
Step 1: Check statement (A).
Radioactive decay obeys:
$$\frac{dN}{dt}=-kN$$
This is first-order kinetics.
So statement (A) is correct.
Step 2: Check statement (B).
Surface-catalysed reactions often become zero order when catalyst surface is saturated.
Thermal decomposition of HI on gold surface is a standard example of zero-order reaction.
So (B) is correct.
Step 3: Check statement (C).
Decomposition of H$_2$O$_2$ catalysed by iodide in alkaline medium is treated as first-order in standard syllabus context.
So (C) is correct.
Step 4: Check statement (D).
For second-order reaction:
$$\text{Rate}=k[\text{conc}]^2$$
Unit of rate constant:
$$k=\frac{\text{mol L}^{-1}\text{s}^{-1}}{(\text{mol L}^{-1})^2}
= \text{L mol}^{-1}\text{s}^{-1}$$
So (D) is correct.
Step 5: Check statement (E).
For reaction:
$$\text{CHCl}_3+\text{Cl}_2 \rightarrow \text{CCl}_4+\text{HCl}$$
The experimentally observed reaction is photochemical chain reaction and does not follow:
$$Rate=k[\text{CHCl}_3][\text{Cl}_2]$$
Hence this given rate law is incorrect.
Step 6: Final answer.
Therefore incorrect statement is:
$$\boxed{\text{Option (E)}}$$
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