Question:

Which of the following statement is/are correct with respect to bacterial transduction
Statement (A): A partially diploid bacterial cell for the transduced gene can be produced.
Statement (B): The partial diploid case is resulted due to a complete transduction phenomenon
In light of the above statements, choose the most appropriate answer from the options given below:

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Stable integration of donor DNA represents complete transduction, while unintegrated donor DNA leads to transient partial diploidy in abortive transduction.
  • Both A and B are correct.
  • B is correct but A is incorrect.
  • A is correct but B is incorrect.
  • Both A and B are incorrect.
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Transduction is the bacteriophage-mediated transfer of genetic material between bacterial cells.
Following entry into the recipient host, the transferred donor DNA can undergo either complete transduction or abortive transduction.

Step 2: Detailed Explanation:

In complete transduction, the linear donor DNA fragment undergoes homologous recombination and integrates stably into the recipient's chromosome.
This process replaces the recipient's native allele, resulting in a stable recombinant haploid cell.
In abortive transduction, the transferred donor DNA fragment fails to integrate into the host chromosome.
It remains as an unintegrated, non-replicating molecule in the cytoplasm.
Because the host cell contains its own copy of the gene as well as the newly introduced copy on the free fragment, it becomes a partial diploid (merodiploid) for those alleles.
Since the free fragment cannot replicate, it is passed to only one daughter cell during each division, maintaining the partial diploid state in only a single cell lineage.
Thus, Statement (A) is correct as partial diploids can be produced.
However, this partial diploidy is a hallmark of abortive transduction rather than complete transduction, making Statement (B) incorrect.

Step 3: Final Answer:

Hence, the correct option is (C).
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