Which of the following solvents is having its lowest Ebullioscopic constant?Solvent Boiling Point (K) Chloroform 334.4 Diethyl Ether 307.8 Benzene 353.3 Carbon disulphide 319.4
Choose the correct answer from the options given below:
| Solvent | Boiling Point (K) |
|---|---|
| Chloroform | 334.4 |
| Diethyl Ether | 307.8 |
| Benzene | 353.3 |
| Carbon disulphide | 319.4 |
- Chloroform
- Diethyl Ether
- Benzene
- Carbon disulphide
The Correct Option is B
Solution and Explanation
The ebullioscopic constant (\(k_b\)) of a solvent is indicative of how much its boiling point will increase when a solute is added to it. Generally, \(k_b\) is dependent on the solvent's specific properties, but a general trend can be observed: the lower the boiling point, the lower the ebullioscopic constant. To determine which solvent has the lowest ebullioscopic constant, we will compare their boiling points.
| Solvent | Boiling Point (K) |
|---|---|
| Chloroform | 334.4 |
| Diethyl Ether | 307.8 |
| Benzene | 353.3 |
| Carbon Disulphide | 319.4 |
Analyzing the boiling points of the provided solvents:
- Chloroform: 334.4 K
- Diethyl Ether: 307.8 K
- Benzene: 353.3 K
- Carbon Disulphide: 319.4 K
Among these, Diethyl Ether has the lowest boiling point at 307.8 K. Therefore, it is expected to have the lowest ebullioscopic constant.
Thus, the correct answer is Diethyl Ether.
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