Step 1: Recall the idea
Anionic hydrolysis means the anion of the salt reacts with water and gives \(OH^-\). This happens when the anion comes from a weak acid and the cation comes from a strong base. The solution becomes basic.
Step 2: Check each salt
\(Na_2CO_3\) is made from strong base NaOH and weak acid \(H_2CO_3\). The carbonate ion hydrolyses: \(CO_3^{2-} + H_2O \rightleftharpoons HCO_3^- + OH^-\).
\(CuSO_4\), \(NH_4Cl\) and \(FeCl_3\) contain weak-base cations (\(Cu^{2+}\), \(NH_4^+\), \(Fe^{3+}\)) and anions of strong acids, so they undergo cationic hydrolysis and give acidic solutions.
Final Answer:
Only Na2CO3 undergoes anionic hydrolysis.
\[ \boxed{\text{(B)}\ Na_2CO_3} \]