Question:

Which of the following pairs of ions will have same spin only magnetic moment values within the pair?
A. Zn2+, Ti2+
B. Cr2+, Fe2+
C. Ti3+, Cu2+
D. V2+, Cu+
Choose the correct answer from the options given below:

Updated On: May 1, 2026
  • C and D only
  • A and D only
  • A and B only
  • B and C only
Show Solution
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The Correct Option is D

Solution and Explanation

To determine which pairs of ions have the same spin-only magnetic moment values, let's calculate the spin-only magnetic moment for each ion using the formula:

\(\mu = \sqrt{n(n+2)}\) 

where \(n\) is the number of unpaired electrons.

  1. For Zn2+:
    • Electronic configuration of Zn: [Ar] 3d10 4s2
    • Zn2+: [Ar] 3d10
    • Unpaired electrons: 0
    • Spin-only magnetic moment, \(\mu = 0\)
  2. For Ti2+:
    • Electronic configuration of Ti: [Ar] 3d2 4s2
    • Ti2+: [Ar] 3d2
    • Unpaired electrons: 2
    • Spin-only magnetic moment, \(\mu = \sqrt{2(2+2)} = 2.83 \, \text{BM}\)
  3. For Cr2+:
    • Electronic configuration of Cr: [Ar] 3d5 4s1
    • Cr2+: [Ar] 3d4
    • Unpaired electrons: 4
    • Spin-only magnetic moment, \(\mu = \sqrt{4(4+2)} = 4.90 \, \text{BM}\)
  4. For Fe2+:
    • Electronic configuration of Fe: [Ar] 3d6 4s2
    • Fe2+: [Ar] 3d6
    • Unpaired electrons: 4
    • Spin-only magnetic moment, \(\mu = \sqrt{4(4+2)} = 4.90 \, \text{BM}\)
  5. For Ti3+:
    • Electronic configuration of Ti: [Ar] 3d2 4s2
    • Ti3+: [Ar] 3d1
    • Unpaired electrons: 1
    • Spin-only magnetic moment, \(\mu = \sqrt{1(1+2)} = 1.73 \, \text{BM}\)
  6. For Cu2+:
    • Electronic configuration of Cu: [Ar] 3d10 4s1
    • Cu2+: [Ar] 3d9
    • Unpaired electrons: 1
    • Spin-only magnetic moment, \(\mu = \sqrt{1(1+2)} = 1.73 \, \text{BM}\)
  7. For V2+:
    • Electronic configuration of V: [Ar] 3d3 4s2
    • V2+: [Ar] 3d3
    • Unpaired electrons: 3
    • Spin-only magnetic moment, \(\mu = \sqrt{3(3+2)} = 3.87 \, \text{BM}\)
  8. For Cu+:
    • Electronic configuration of Cu: [Ar] 3d10 4s1
    • Cu+: [Ar] 3d10
    • Unpaired electrons: 0
    • Spin-only magnetic moment, \(\mu = 0\)

Now, comparing the calculated values to find ions with the same spin-only magnetic moment:

  • Cr2+ and Fe2+ both have \(\mu = 4.90 \, \text{BM}\).
  • Ti3+ and Cu2+ both have \(\mu = 1.73 \, \text{BM}\).

Thus, the correct answer is B and C only.

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