Question:
Which of the following \(n\) mole compound is obtained when \(2n\) moles of \(\text{C}_6\text{H}_5\text{Cl}\) treated of with \(2n\) mole sodium atom in dry ether?
Which of the following \(n\) mole compound is obtained when \(2n\) moles of \(\text{C}_6\text{H}_5\text{Cl}\) treated of with \(2n\) mole sodium atom in dry ether?
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Two aryl halides couple with sodium in dry ether to give biphenyl (Fittig reaction).
Updated On: Oct 1, 2026
- Biphenyl
- Toluene
- Phenol
- Benzene
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
When an aryl halide is heated with sodium metal in dry ether, two aryl groups join. This is the Fittig reaction.
Step 2: Balanced Reaction:
\[ 2\,\text{C}_6\text{H}_5\text{Cl} + 2\,\text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5-\text{C}_6\text{H}_5 + 2\,\text{NaCl} \]
So \(2n\) mol of chlorobenzene and \(2n\) mol of sodium give \(n\) mol of biphenyl.
Step 3: Check the Other Options:
Benzene would form by reduction with a reagent such as Zn and acid. Phenol needs hydrolysis (aqueous NaOH at high temperature and pressure). Toluene needs methyl halide in the Wurtz-Fittig reaction, which is absent here. So (A) is correct.
Final Answer:
The product is biphenyl, option (A). \[ \boxed{\text{(A) Biphenyl}} \]
When an aryl halide is heated with sodium metal in dry ether, two aryl groups join. This is the Fittig reaction.
Step 2: Balanced Reaction:
\[ 2\,\text{C}_6\text{H}_5\text{Cl} + 2\,\text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5-\text{C}_6\text{H}_5 + 2\,\text{NaCl} \]
So \(2n\) mol of chlorobenzene and \(2n\) mol of sodium give \(n\) mol of biphenyl.
Step 3: Check the Other Options:
Benzene would form by reduction with a reagent such as Zn and acid. Phenol needs hydrolysis (aqueous NaOH at high temperature and pressure). Toluene needs methyl halide in the Wurtz-Fittig reaction, which is absent here. So (A) is correct.
Final Answer:
The product is biphenyl, option (A). \[ \boxed{\text{(A) Biphenyl}} \]
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