Question:
Which of the following molecules have regular geometry without Lone pair of electrons in the valence shell of central atom?
Which of the following molecules have regular geometry without Lone pair of electrons in the valence shell of central atom?
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Look for the central atom with all valence electrons used in bond pairs.
Updated On: Nov 13, 2026
- \(NH_3\)
- \(PCl_3\)
- \(BF_3\)
- \(ICl_3\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Regular geometry without a lone pair means the central atom has only bond pairs.
Step 2: Check Each Molecule
\(\text{NH}_3\) and \(\text{PCl}_3\) have one lone pair on the central atom, so they are pyramidal. \(\text{ICl}_3\) has two lone pairs and is T-shaped.
Step 3: Correct Molecule
In \(\text{BF}_3\) boron has three bond pairs and no lone pair, giving a regular trigonal planar shape, option (C).
Final Answer:
BF3 has regular geometry with no lone pair on boron. \[ \boxed{\text{(C) }BF_3} \]
Regular geometry without a lone pair means the central atom has only bond pairs.
Step 2: Check Each Molecule
\(\text{NH}_3\) and \(\text{PCl}_3\) have one lone pair on the central atom, so they are pyramidal. \(\text{ICl}_3\) has two lone pairs and is T-shaped.
Step 3: Correct Molecule
In \(\text{BF}_3\) boron has three bond pairs and no lone pair, giving a regular trigonal planar shape, option (C).
Final Answer:
BF3 has regular geometry with no lone pair on boron. \[ \boxed{\text{(C) }BF_3} \]
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