Question

What is the hybridization of the central sulfur atom in \(SF_6\)?

• A. \(sp^3\)
• B. \(sp^3d\)
• C. \(sp^3d^2\)
• D. \(sp^2\)

Hint:

Hybridization vs steric number: 2 → \(sp\) 3 → \(sp^2\) 4 → \(sp^3\) 5 → \(sp^3d\) 6 → \(sp^3d^2\)

Answer 1

The Correct Option is C

Concept: Hybridization depends on the steric number, which is the total number of sigma bonds and lone pairs around the central atom. \[ \text{Steric number} = \text{number of bonded atoms} + \text{lone pairs} \]

Step 1: Identify bonding in \(SF_6\). Sulfur is the central atom and forms bonds with six fluorine atoms. \[ \text{Number of } \sigma \text{ bonds} = 6 \] \[ \text{Lone pairs on sulfur} = 0 \]

Step 2: Determine steric number. \[ \text{Steric number} = 6 \]

Step 3: Determine hybridization. Steric number \(6\) corresponds to \[ sp^3d^2 \] This gives an octahedral geometry. Thus, the hybridization of sulfur in \(SF_6\) is \[ \boxed{sp^3d^2} \]