Question:
Which of the following mixtures show negative deviation from Raoult's law?
Which of the following mixtures show negative deviation from Raoult's law?
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Mixtures with strong intermolecular forces (like H-bonding) between unlike molecules show negative deviation from Raoult's law.
Updated On: Jun 19, 2026
- II & III only
- III & IV only
- I & II only
- I & III only
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The Correct Option is C
Solution and Explanation
Step 1: Understanding negative deviation.
Negative deviation from Raoult's law occurs when intermolecular attractions between unlike molecules are stronger than those between like molecules.
Step 2: Analyze given mixtures.
- (I) \(CHCl_3 + (CH_3)_2CO\): Strong hydrogen bonding leads to negative deviation.
- (II) \(C_6H_5OH + C_6H_5NH_2\): Hydrogen bonding exists, causing negative deviation.
- (III) \(C_2H_5OH + (CH_3)_2CO\): Some hydrogen bonding, but deviation depends on relative strengths.
- (IV) \(C_6H_6 + C_6H_5CH_3\): Weak van der Waals interactions, typically obeys Raoult's law.
Step 3: Identify negative deviation mixtures.
Hence, mixtures I & II show negative deviation.
Step 4: Final conclusion.
The correct answer is: \[ \boxed{\text{I \& II only}} \]
Negative deviation from Raoult's law occurs when intermolecular attractions between unlike molecules are stronger than those between like molecules.
Step 2: Analyze given mixtures.
- (I) \(CHCl_3 + (CH_3)_2CO\): Strong hydrogen bonding leads to negative deviation.
- (II) \(C_6H_5OH + C_6H_5NH_2\): Hydrogen bonding exists, causing negative deviation.
- (III) \(C_2H_5OH + (CH_3)_2CO\): Some hydrogen bonding, but deviation depends on relative strengths.
- (IV) \(C_6H_6 + C_6H_5CH_3\): Weak van der Waals interactions, typically obeys Raoult's law.
Step 3: Identify negative deviation mixtures.
Hence, mixtures I & II show negative deviation.
Step 4: Final conclusion.
The correct answer is: \[ \boxed{\text{I \& II only}} \]
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