Question:
Which of the following is formed when \(SO_3\) is absorbed by concentrated \(H_2SO_4\)?
Which of the following is formed when \(SO_3\) is absorbed by concentrated \(H_2SO_4\)?
Show Hint
Oleum is formed by dissolving \(SO_3\) in concentrated sulphuric acid:
\[
SO_3+H_2SO_4\rightarrow H_2S_2O_7
\]
It is also called fuming sulphuric acid.
Updated On: Jun 22, 2026
- \(H_2S_2O_8\)
- \(H_2S_2O_3\)
- \(H_2S_2O_7\)
- \(H_2S_2O_5\)
Show Solution
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The Correct Option is C
Solution and Explanation
Step 1: Identify the reaction involved.
Sulphur trioxide reacts with concentrated sulphuric acid to form oleum.
The reaction is \[ SO_3+H_2SO_4\rightarrow H_2S_2O_7 \]
Step 2: Name the product formed.
The compound \[ H_2S_2O_7 \] is called pyrosulphuric acid or oleum.
Oleum is an important intermediate in the Contact Process for manufacturing sulphuric acid.
Step 3: Final conclusion.
Hence, the compound formed is \[ \boxed{H_2S_2O_7} \]
Sulphur trioxide reacts with concentrated sulphuric acid to form oleum.
The reaction is \[ SO_3+H_2SO_4\rightarrow H_2S_2O_7 \]
Step 2: Name the product formed.
The compound \[ H_2S_2O_7 \] is called pyrosulphuric acid or oleum.
Oleum is an important intermediate in the Contact Process for manufacturing sulphuric acid.
Step 3: Final conclusion.
Hence, the compound formed is \[ \boxed{H_2S_2O_7} \]
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