Question:
Which of the following is an equivalent cyclic process corresponding to the thermodynamic cyclic given in the figure ? where, \(1\to2\) is adiabatic.
(Graphs are schematic and are not to scale)
Which of the following is an equivalent cyclic process corresponding to the thermodynamic cyclic given in the figure ? where, \(1\to2\) is adiabatic.
(Graphs are schematic and are not to scale)
(Graphs are schematic and are not to scale)
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Identify the processes: 1 to 2 adiabatic expansion, 2 to 3 isobaric compression, 3 to 1 isochoric heating, and see how each looks on a V-T graph.
Updated On: Nov 5, 2026
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The Correct Option is B
Solution and Explanation
From the P-V diagram: \(1\to2\) is adiabatic expansion (\(TV^{\gamma-1}=\) const, so V rises while T falls along a curve); \(2\to3\) is at constant P with V decreasing (\(V\propto T\), a straight line through the origin on a V-T graph); \(3\to1\) is at constant V with P rising, so T rises (a horizontal line to the right on a V-T graph).
Option (1): the \(2\to3\) path is curved, so it is not isobaric. Option (3): \(2\to3\) is horizontal (constant V), wrong. Option (4): \(1\to2\) is a straight line, but an adiabat on V-T is a curve. Option (2): curve for \(1\to2\), an inclined straight line (isobaric) for \(2\to3\) and a horizontal line for \(3\to1\). This matches.
Answer: (2) (V-T graph with 1 to 2 curved, 2 to 3 straight inclined line, 3 to 1 horizontal)
Option (1): the \(2\to3\) path is curved, so it is not isobaric. Option (3): \(2\to3\) is horizontal (constant V), wrong. Option (4): \(1\to2\) is a straight line, but an adiabat on V-T is a curve. Option (2): curve for \(1\to2\), an inclined straight line (isobaric) for \(2\to3\) and a horizontal line for \(3\to1\). This matches.
Answer: (2) (V-T graph with 1 to 2 curved, 2 to 3 straight inclined line, 3 to 1 horizontal)
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