Question:

Which of the following is a correct set of four quantum numbers for a 4d orbital?

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Always remember: \[ |m_l| \leq l \] If \(m_l\) is greater than \(l\), the quantum number set is invalid.
Updated On: May 19, 2026
  • \( (4, 3, 2, 1/2) \)
  • \( (4, 2, 1, 1/2) \)
  • \( (4, 1, 2, 1/2) \)
  • None of these
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The Correct Option is B

Solution and Explanation

Concept: Quantum numbers describe the position and state of an electron in an atom.
• Principal quantum number \(n\): Specifies shell.
• Azimuthal quantum number \(l\): Specifies orbital shape.
• Magnetic quantum number \(m_l\): Specifies orientation.
• Spin quantum number \(m_s\): Specifies spin direction. For orbital notation: \[ s \rightarrow 0, \quad p \rightarrow 1, \quad d \rightarrow 2, \quad f \rightarrow 3 \]

Step 1:
Determining \(n\) and \(l\) for 4d orbital.
For a 4d orbital: \[ n = 4, \qquad l = 2 \]

Step 2:
Determining allowed values of \(m_l\) and \(m_s\).
For \(l = 2\): \[ m_l = -2, -1, 0, +1, +2 \] and \[ m_s = \pm \frac{1}{2} \]

Step 3:
Checking the options.

• \( (4,3,2,1/2) \): Represents 4f orbital.
• \( (4,2,1,1/2) \): All values are valid.
• \( (4,1,2,1/2) \): Invalid because for \(l=1\), \(m_l\) cannot be 2. Hence, the correct answer is option (2).
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