Question:
Which of the following hot aqueous solutions is used to dip carbon rods of \(\text{H}_2-\text{O}_2\) fuel cell ?
Which of the following hot aqueous solutions is used to dip carbon rods of \(\text{H}_2-\text{O}_2\) fuel cell ?
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The H\(_2\)-O\(_2\) fuel cell uses a hot concentrated alkaline electrolyte, KOH.
Updated On: Oct 1, 2026
- \(\text{KCl}\)
- \(\text{KOH}\)
- \(\text{H}_2\text{SO}_4\)
- \(\text{NH}_4\text{Cl}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
In the H\(_2\)-O\(_2\) fuel cell, porous carbon electrodes carrying a catalyst dip into a hot aqueous solution of an alkali.
Step 2: Detailed Explanation
The electrolyte is aqueous KOH. At the anode, hydrogen is oxidised: \(2\text{H}_2 + 4\text{OH}^- \to 4\text{H}_2\text{O} + 4e^-\).
At the cathode, oxygen is reduced: \(\text{O}_2 + 2\text{H}_2\text{O} + 4e^- \to 4\text{OH}^-\).
The OH\(^-\) ions carry current through the solution, so a hydroxide solution is needed.
Final Answer:
The carbon rods dip in hot aqueous KOH, option (B). \[ \boxed{\text{KOH (B)}} \]
In the H\(_2\)-O\(_2\) fuel cell, porous carbon electrodes carrying a catalyst dip into a hot aqueous solution of an alkali.
Step 2: Detailed Explanation
The electrolyte is aqueous KOH. At the anode, hydrogen is oxidised: \(2\text{H}_2 + 4\text{OH}^- \to 4\text{H}_2\text{O} + 4e^-\).
At the cathode, oxygen is reduced: \(\text{O}_2 + 2\text{H}_2\text{O} + 4e^- \to 4\text{OH}^-\).
The OH\(^-\) ions carry current through the solution, so a hydroxide solution is needed.
Final Answer:
The carbon rods dip in hot aqueous KOH, option (B). \[ \boxed{\text{KOH (B)}} \]
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