Question:
Which of the following expression is correct?
Which of the following expression is correct?
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Remember: $\Delta G^\circ = -RT \ln K$ links thermodynamics with equilibrium.
Updated On: Mar 18, 2026
- $\Delta G = -RT \ln K$
- $\Delta G = \dfrac{1}{RT^2} \ln K$
- $\Delta G^\circ = -RT \ln K$
- $\Delta G^\circ = -\dfrac{1}{RT^2} \ln K$
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The Correct Option is C
Solution and Explanation
The standard Gibbs free energy change is related to the equilibrium constant as:
$\Delta G^\circ = -RT \ln K$
$\Delta G^\circ = -RT \ln K$
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