Question:
Which of the following compound has square pyramidal structure?
Which of the following compound has square pyramidal structure?
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Count bond pairs and lone pairs on xenon in each compound and use VSEPR.
Updated On: Oct 1, 2026
- \(\text{XeF}_4\)
- \(\text{XeF}_6\)
- \(\text{XeO}_3\)
- \(\text{XeOF}_4\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
VSEPR theory gives the shape from the number of electron pairs around the central atom. Lone pairs also take up space, so they change the shape from the ideal one.
Step 2: Key Formula or Approach:
For \(\text{XeOF}_4\): xenon has \(8\) valence electrons. Four go to F, two go to the \(\text{Xe=O}\) bond and two stay as one lone pair. That gives \(5\) bonded atoms and \(1\) lone pair, so \(sp^3d^2\) hybridisation.
Step 3: Detailed Explanation:
Six electron regions give an octahedral arrangement. One position is a lone pair, so the molecule is square pyramidal.
Check the others.
\(\text{XeF}_4\): 4 bonds and 2 lone pairs, square planar.
\(\text{XeF}_6\): 6 bonds and 1 lone pair, distorted octahedral.
\(\text{XeO}_3\): 3 bonds and 1 lone pair, trigonal pyramidal.
Final Answer:
Only \(\text{XeOF}_4\) is square pyramidal, option (D). \[ \boxed{\text{XeOF}_4} \]
VSEPR theory gives the shape from the number of electron pairs around the central atom. Lone pairs also take up space, so they change the shape from the ideal one.
Step 2: Key Formula or Approach:
For \(\text{XeOF}_4\): xenon has \(8\) valence electrons. Four go to F, two go to the \(\text{Xe=O}\) bond and two stay as one lone pair. That gives \(5\) bonded atoms and \(1\) lone pair, so \(sp^3d^2\) hybridisation.
Step 3: Detailed Explanation:
Six electron regions give an octahedral arrangement. One position is a lone pair, so the molecule is square pyramidal.
Check the others.
\(\text{XeF}_4\): 4 bonds and 2 lone pairs, square planar.
\(\text{XeF}_6\): 6 bonds and 1 lone pair, distorted octahedral.
\(\text{XeO}_3\): 3 bonds and 1 lone pair, trigonal pyramidal.
Final Answer:
Only \(\text{XeOF}_4\) is square pyramidal, option (D). \[ \boxed{\text{XeOF}_4} \]
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