Question:
Which of the following binary solution exhibits higher vapor pressure than the vapour pressure of its pure components at same temprecure?
Which of the following binary solution exhibits higher vapor pressure than the vapour pressure of its pure components at same temprecure?
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A solution with vapour pressure higher than its pure components shows positive deviation, where mixing weakens attractions.
Updated On: Nov 12, 2026
- Benzene + Toluene
- Phenol + aniline
- ethanol + acetone
- chloroform + acetone
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
A vapour pressure higher than expected shows positive deviation from Raoult's law.
This happens when the A-B attractions are weaker than the A-A and B-B attractions.
Step 2: Analyse the Options
Benzene with toluene forms a nearly ideal solution.
Phenol with aniline and chloroform with acetone show negative deviation because of hydrogen bonding between unlike molecules.
Ethanol with acetone shows positive deviation because acetone breaks the hydrogen bonds of ethanol.
Step 3: Compare the options
Ethanol and acetone is option (C).
Final Answer:
Ethanol with acetone shows positive deviation and a higher vapour pressure. \[ \boxed{\text{(C) }\text{ethanol + acetone}} \]
A vapour pressure higher than expected shows positive deviation from Raoult's law.
This happens when the A-B attractions are weaker than the A-A and B-B attractions.
Step 2: Analyse the Options
Benzene with toluene forms a nearly ideal solution.
Phenol with aniline and chloroform with acetone show negative deviation because of hydrogen bonding between unlike molecules.
Ethanol with acetone shows positive deviation because acetone breaks the hydrogen bonds of ethanol.
Step 3: Compare the options
Ethanol and acetone is option (C).
Final Answer:
Ethanol with acetone shows positive deviation and a higher vapour pressure. \[ \boxed{\text{(C) }\text{ethanol + acetone}} \]
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