Question

For the reaction, ${CO}_{(g)}+{Cl}_{2(g)}\rightleftharpoons {COCl}_{2(g)}$, then $K_p/K_c$ is equal to:

• (A) $\sqrt{RT}$
• (B) $RT$
• (C) $\frac{1}{RT}$
• (D) $1.0$

Answer 1

The Correct Option is C

Explanation:
Given equation is:$CO(g)+{Cl}_2(g)\rightleftharpoons {COCl}_2(g)$We know that:$K_p=K_p[RT{]}^n$Where,$n=$ Concentration of products - concentration of reactants$n=1-2=-1$Therefore, $K_p=K_c[RT{]}^{\mathrm{\Delta }n}$;$\therefore \frac{K_p}{K_c}=[RT{]}^{-1}$$=\frac{1}{RT}$Hence, the correct option is (C).