Concept:
Heisenberg uncertainty principle states that the exact position and momentum of a particle cannot be determined simultaneously with absolute precision.
Mathematically:
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This principle has several important consequences in quantum mechanics and atomic physics.
Step 1: Analyze Statement A.
Statement A says:
“Non-existence of electron inside the nucleus”
Suppose an electron were confined inside the nucleus.
Since nuclear radius is extremely small:
\[
\Delta x \approx 10^{-15}\ \text{m}
\]
By uncertainty principle:
\[
\Delta p \geq \frac{h}{4\pi \Delta x}
\]
Thus momentum uncertainty becomes extremely large.
This would imply:
• Very large kinetic energy for electron
Such enormous energy is inconsistent with observed nuclear stability.
Therefore electrons cannot exist inside nucleus permanently.
Hence Statement A is correct.
Step 2: Analyze Statement B.
Statement B says:
“Particles must have minimum (Ground state) energy”
If a particle had exactly zero energy:
• Momentum would become zero.
• Position and momentum would both become definite.
This violates uncertainty principle.
Therefore every quantum particle must possess:
\[
\boxed{
\text{Minimum non-zero energy}
}
\]
called zero point or ground state energy.
Hence Statement B is correct.
Step 3: Analyze Statement C.
Statement C says:
“It defines the probabilistic nature (Orbital) of electrons in atoms”
Because exact position and momentum cannot be simultaneously determined:
• Electrons cannot move in sharp definite paths.
• Electrons are described by probability distributions.
Thus orbitals arise naturally from uncertainty principle and wave mechanics.
Hence Statement C is correct.
Step 4: Analyze Statement D carefully.
Statement D says:
“It limits the precision with which we can measure a football's position and speed simultaneously”
Technically uncertainty principle applies to all objects.
However:
• For macroscopic objects like footballs, Planck's constant is extremely small.
• Resulting uncertainty is practically negligible.
Thus this is not considered a meaningful practical consequence/application in classical systems.
Hence Statement D is not taken as correct in this context.
Step 5: Determine the correct combination.
Correct statements are:
\[
A,\ B,\ C
\]
Incorrect statement:
\[
D
\]
Therefore:
\[
\boxed{
A,\ B\ \&\ C\ \text{Only}
}
\]
Step 6: Choose the correct answer.
Hence the correct option is:
\[
\boxed{(3)}
\]
Final Conclusion:
Valid consequences/applications of uncertainty principle are:
• Non-existence of electron inside nucleus
• Existence of minimum ground state energy
• Probabilistic electron orbitals
Hence, the correct answer is:
\[
\boxed{(3)}
\]