Question

If a man with blood group AB marries a women with type O, point out the blood group of their children?

• A. All Children will have blood group A
• B. All children will have blood group B
• C. Half of the Children have blood group A and half type B blood
• D. All have blood group type O

Hint:

AB parent: \[ I^A I^B \] O parent: \[ ii \] Children: \[ I^Ai \text{ or } I^Bi \]

Answer 1

The Correct Option is C

Concept: ABO blood grouping is controlled by: \[ \boxed{ I^A,\ I^B,\ i } \] where:
• \(I^A\) produces antigen A
• \(I^B\) produces antigen B
• \(i\) produces no antigen

Step 1: Write genotype of parents. Man with blood group AB: \[ \boxed{ I^A I^B } \] Woman with blood group O: \[ \boxed{ ii } \]

Step 2: Determine gametes. Gametes produced by father: \[ I^A,\ I^B \] Gametes produced by mother: \[ i,\ i \]

Step 3: Prepare genetic combinations. Possible offspring combinations: \[ I^A \times i \rightarrow I^A i \] \[ I^B \times i \rightarrow I^B i \] Thus children can have:
• Blood group A
• Blood group B

Step 4: Calculate proportions. Probability: \[ 50% \rightarrow \text{Blood group A} \] \[ 50% \rightarrow \text{Blood group B} \] Thus: \[ \boxed{ \text{Half A and half B} } \]

Step 5: Choose correct answer. Hence correct option is: \[ \boxed{(3)} \] Final Conclusion: Cross: \[ I^A I^B \times ii \] produces: \[ 50% \text{ A group} \quad \text{and} \quad 50% \text{ B group} \] Hence correct answer is: \[ \boxed{(3)} \]