Step 1: Classify each salt
(A) KNO\(_3\): strong base + strong acid, neutral, pH \(=7\).
(B) Na\(_2\)CO\(_3\): strong base + weak acid, basic, pH \(>7\).
(C) CH\(_3\)COONH\(_4\): weak acid + weak base with nearly equal strengths, about neutral.
(D) CuCl\(_2\): weak base Cu(OH)\(_2\) + strong acid HCl, acidic.
Step 2: Reason for (D)
Cu\(^{2+}\) hydrolyses: \(\text{Cu}^{2+}+2\text{H}_2\text{O}\rightleftharpoons\text{Cu(OH)}_2+2\text{H}^+\). Extra H\(^+\) makes pH \(<7\).
Final Answer:
CuCl\(_2\) solution is acidic, option (D).
\[ \boxed{\text{(D) CuCl}_2} \]