The given sequence is \( 5, 9, 16, 29, 54, \ldots \) and each term can in fact be written in closed form, which lets us evaluate every option directly instead of extending the recurrence term by term.
Writing \( a_n \) for the \( n \)-th term (so \( a_1 = 5, a_2 = 9, a_3 = 16, a_4 = 29, a_5 = 54 \)), the ratio of consecutive gaps roughly doubles each time, which suggests a solution of the form \( a_n = C \cdot 2^{n-1} + n + 1 \). Substituting \( a_1 = 5 \) gives \( C + 2 = 5 \), so \( C = 3 \), and the closed form becomes:
Checking this against the known terms: \( a_2 = 3(2) + 3 = 9 \), \( a_3 = 3(4) + 4 = 16 \), \( a_4 = 3(8) + 5 = 29 \), \( a_5 = 3(16) + 6 = 54 \), all match, so the formula is confirmed.
The seventh term of the sequence is therefore \( 200 \).
the correct answer is Option B: 200.


| 2 | 4 | 6 | 8 | 10 |
| 2 | 14 | 34 | ?? | 98 |
