Question:

Which group from following is responsible for $(-)\mathrm{R}$ effect?

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To easily spot a $(-)\mathrm{R}$ group, look for a double or triple bond connected to an electronegative heteroatom (like $\mathrm{C=O}$, $\mathrm{N=O}$, or $\mathrm{C\equiv N}$) directly attached to the chain. Groups containing only lone pairs on the linking atom ($\mathrm{-O-}$, $\mathrm{-N-}$, $\mathrm{-X}$) always exert a $(+)\mathrm{R}$ effect.
Updated On: Jun 11, 2026
  • $-\mathrm{COOR}$
  • $-\mathrm{OR}$
  • $-\mathrm{OH}$
  • $-\mathrm{NHR}$
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
We need to identify the functional group from the given options that is responsible for producing a negative resonance effect ($(-)\mathrm{R}$ effect).

Step 2: Key Formula or Approach:
The resonance effect ($\mathrm{R}$ effect) describes the redistribution of electron density in a conjugated system via $\pi$-bond delocalization:

$(+)\mathrm{R}$ effect (Electron-donating): Occurs when an atom directly attached to the conjugated system possesses a lone pair of electrons available for donation into the ring or chain.

$(-)\mathrm{R}$ effect (Electron-withdrawing): Occurs when the substituent contains electronegative atoms linked by multiple bonds ($\mathrm{C=O}$, $\mathrm{-C\equiv N}$, $-\mathrm{NO_2}$), drawing electron density away from the conjugated system towards itself.

Step 3: Detailed Explanation:
Let's examine the structural electron distribution of each option:

• $-\mathrm{COOR}$ (Ester group): Contains a strongly polarized carbonyl group ($\mathrm{C=O}$). The $\pi$-electrons can be pulled up towards the highly electronegative carbonyl oxygen atom, withdrawing $\pi$-electron density from any adjacent conjugated system through resonance. This defines a classic $(-)\mathrm{R}$ effect.

• $-\mathrm{OR}$ (Alkoxy group): The oxygen atom has two lone pairs directly adjacent to the bond axis, allowing it to donate electron density into a conjugated system via resonance ($(+)\mathrm{R}$ effect).

• $-\mathrm{OH}$ (Hydroxyl group): Possesses lone pairs on the oxygen atom that participate in conjugation by electron donation ($(+)\mathrm{R}$ effect).

• $-\mathrm{NHR}$ (Alkylamino group): The nitrogen atom bears a lone pair of electrons that is readily donated into a conjugated pathway ($(+)\mathrm{R}$ effect).
Therefore, only the $-\mathrm{COOR}$ group functions as a resonance electron-withdrawing group.

Step 4: Final Answer:
The group responsible for the $(-)\mathrm{R}$ effect is $-\mathrm{COOR}$, which matches option (A).
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