Step 1: Understanding the Concept:
A monocarboxylic acid has exactly one \(-\text{COOH}\) group.
Step 2: Check the Options:
Toluic acid: methylbenzoic acid, one COOH.
Acrylic acid: \(\text{CH}_2=\text{CH-COOH}\), one COOH.
Phthalic acid: benzene-1,2-dicarboxylic acid, two COOH.
Isobutyric acid: \((\text{CH}_3)_2\text{CH-COOH}\), one COOH.
Step 3: Conclusion:
Phthalic acid has two carboxyl groups, so it is a dicarboxylic acid and not a monocarboxylic acid.
Final Answer:
Phthalic acid is dicarboxylic, option (C).
\[ \boxed{\text{(C) Phthalic acid}} \]