Question:
Which from following amines when heated with ethanolic KOH and chloroform forms aryl isocyanide ?
Which from following amines when heated with ethanolic KOH and chloroform forms aryl isocyanide ?
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Only primary amines give the carbylamine reaction.
Updated On: Oct 1, 2026
- Benzenamine
- N -methylaniline
- N, N - Dimethylaniline
- Ethylethanamine
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Heating a primary amine with chloroform and alcoholic KOH gives an isocyanide (carbylamine), which has a foul smell. This is the carbylamine reaction, a test for primary amines.
Step 2: Check the options:
Benzenamine (aniline) is \(\text{C}_6\text{H}_5\text{NH}_2\), a primary aromatic amine, so it gives phenyl isocyanide.
N-methylaniline is secondary, N,N-dimethylaniline is tertiary, and ethylethanamine (diethylamine) is secondary. They do not give this reaction.
\[ \text{C}_6\text{H}_5\text{NH}_2 + \text{CHCl}_3 + 3\text{KOH} \rightarrow \text{C}_6\text{H}_5\text{NC} + 3\text{KCl} + 3\text{H}_2\text{O} \]
Final Answer:
Benzenamine is the primary amine, option (A). \[ \boxed{\text{Benzenamine}} \]
Heating a primary amine with chloroform and alcoholic KOH gives an isocyanide (carbylamine), which has a foul smell. This is the carbylamine reaction, a test for primary amines.
Step 2: Check the options:
Benzenamine (aniline) is \(\text{C}_6\text{H}_5\text{NH}_2\), a primary aromatic amine, so it gives phenyl isocyanide.
N-methylaniline is secondary, N,N-dimethylaniline is tertiary, and ethylethanamine (diethylamine) is secondary. They do not give this reaction.
\[ \text{C}_6\text{H}_5\text{NH}_2 + \text{CHCl}_3 + 3\text{KOH} \rightarrow \text{C}_6\text{H}_5\text{NC} + 3\text{KCl} + 3\text{H}_2\text{O} \]
Final Answer:
Benzenamine is the primary amine, option (A). \[ \boxed{\text{Benzenamine}} \]
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