Step 1: Understanding the Question:
We need the salt whose aqueous solution is basic (pH > 7). This occurs for salts derived from a weak acid and a strong base.
Step 2: Key Formula or Approach:
Hydrolysis of salt:
- Weak acid + strong base → basic solution.
- Strong acid + strong base → neutral.
- Strong acid + weak base → acidic.
- Weak acid + weak base → depends on \(K_a\) and \(K_b\).
Step 3: Detailed Explanation:
- (A) Sodium acetate (CH\(_3\)COONa): weak acid (acetic) + strong base (NaOH) → basic, pH > 7.
- (B) Sodium sulphate (Na\(_2\)SO\(_4\)): strong acid (H\(_2\)SO\(_4\)) + strong base (NaOH) → neutral, pH = 7.
- (C) Copper sulphate (CuSO\(_4\)): strong acid (H\(_2\)SO\(_4\)) + weak base (Cu(OH)\(_2\)) → acidic, pH < 7.
- (D) Ammonium chloride (NH\(_4\)Cl): strong acid (HCl) + weak base (NH\(_3\)) → acidic, pH < 7.
Step 4: Final Answer:
Sodium acetate gives pH > 7, option (A).