Question:

Which actinoid from following has smallest ionic size in \(+3\) state?

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Actinoid contraction: ionic size falls steadily across the series.
Updated On: Oct 1, 2026
  • Pa
  • Cm
  • Fm
  • Lr
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Across the actinoid series, electrons enter the \(5f\) subshell, which shields the nuclear charge poorly. The effective nuclear charge grows, so the size of the \(M^{3+}\) ion decreases steadily. This is called the actinoid contraction.

Step 2: Key Formula or Approach:
Order the elements by atomic number: Pa \((91)\), Cm \((96)\), Fm \((100)\), Lr \((103)\).

Step 3: Detailed Explanation:
The element with the highest atomic number lies furthest along the series and has undergone the most contraction.
Lr (\(Z = 103\)) is the last member of the actinoids, so \(\text{Lr}^{3+}\) is the smallest.
Size order: \(\text{Pa}^{3+} > \text{Cm}^{3+} > \text{Fm}^{3+} > \text{Lr}^{3+}\).

Final Answer:
Lr has the smallest \(+3\) ion, option (D). \[ \boxed{\text{Lr}} \]
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