Question:
When resonance is produced in a series LCR circuit, then which of the following is not correct?
When resonance is produced in a series LCR circuit, then which of the following is not correct?
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At series resonance \(X_L = X_C\), so the impedance is minimum (equal to R), not maximum.
Updated On: Nov 4, 2026
- Current in the circuit is in phase with the applied voltage.
- Inductive and capacitive reactances are equal.
- If R is reduced, the voltage across capacitor will increase.
- Impedance of the circuit is maximum.
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The Correct Option is D
Solution and Explanation
At resonance \(X_L = X_C\), so \(Z = \sqrt{R^2 + (X_L - X_C)^2} = R\), the minimum possible value.
Hence the current \(I = V/R\) is maximum and in phase with the applied voltage (statements 1 and 2 are correct).
Voltage across the capacitor \(V_C = I X_C = \dfrac{V}{R}X_C\): reducing R increases I and \(V_C\) (statement 3 correct).
Statement 4, that the impedance is maximum, is wrong.
Answer: (4) Impedance of the circuit is maximum.
Hence the current \(I = V/R\) is maximum and in phase with the applied voltage (statements 1 and 2 are correct).
Voltage across the capacitor \(V_C = I X_C = \dfrac{V}{R}X_C\): reducing R increases I and \(V_C\) (statement 3 correct).
Statement 4, that the impedance is maximum, is wrong.
Answer: (4) Impedance of the circuit is maximum.
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