Understanding the Phase Relationship in AC Circuits:
In an AC circuit: For a pure inductor, the current \( I \) lags the voltage \( V \) by \( 90^\circ \) (or \(\(\frac{\pi}{2}\) \) radians).
For a pure capacitor, the current \( I \) leads the voltage \( V \) by \( 90^\circ \). For a pure resistor, the current and voltage are in phase, meaning that they reach zero and maximum values simultaneously.
Condition for Instantaneous Current to be Zero When Voltage is Maximum:
The given condition (current is zero when voltage is maximum) implies a \( 90^\circ \) phase difference between the current and voltage.
This situation occurs in:
- A pure inductor, where current lags the voltage by \( 90^\circ \).
- A pure capacitor, where current leads the voltage by \( 90^\circ \).
- A combination of an inductor and capacitor (LC circuit), where the phase difference can also result in current being zero when voltage is maximum.
Conclusion:
Since this phase relationship is possible in a pure inductor, pure capacitor, or an LC combination, the correct answer is Option (4): A, B, and D only.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)