Question:
When NaCl and NaNO\(_3\) separately reacted with H\(_2\)SO\(_4\), the products formed respectively are:
When NaCl and NaNO\(_3\) separately reacted with H\(_2\)SO\(_4\), the products formed respectively are:
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Concentrated H\(_2\)SO\(_4\) acts as a non-volatile strong acid and displaces weaker volatile acids like HCl and HNO\(_3\) from their salts.
Updated On: Jun 19, 2026
- HCl, N\(_2\)O\(_3\)
- HCl, HNO\(_2\)
- HOCl, HNO\(_3\)
- HCl, HNO\(_3\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding reaction of NaCl with concentrated H\(_2\)SO\(_4\).
When sodium chloride reacts with concentrated sulfuric acid, it undergoes acid-base displacement reaction. The stronger acid (H\(_2\)SO\(_4\)) displaces HCl from NaCl: \[ NaCl + H_2SO_4 \rightarrow NaHSO_4 + HCl \] Thus, product formed is hydrogen chloride gas.
Step 2: Understanding reaction of NaNO\(_3\) with H\(_2\)SO\(_4\).
Sodium nitrate reacts with concentrated sulfuric acid to form nitric acid: \[ NaNO_3 + H_2SO_4 \rightarrow NaHSO_4 + HNO_3 \] Thus, product formed is nitric acid.
Step 3: Comparing both reactions.
First reaction produces HCl and second produces HNO\(_3\). These are typical acid displacement reactions involving a stronger acid.
Step 4: Final verification.
No redox change occurs; only proton exchange and acid formation take place.
Step 5: Final conclusion.
Hence, the products formed are HCl and HNO\(_3\).
Final Answer: \[ \boxed{HCl,\ HNO_3} \]
When sodium chloride reacts with concentrated sulfuric acid, it undergoes acid-base displacement reaction. The stronger acid (H\(_2\)SO\(_4\)) displaces HCl from NaCl: \[ NaCl + H_2SO_4 \rightarrow NaHSO_4 + HCl \] Thus, product formed is hydrogen chloride gas.
Step 2: Understanding reaction of NaNO\(_3\) with H\(_2\)SO\(_4\).
Sodium nitrate reacts with concentrated sulfuric acid to form nitric acid: \[ NaNO_3 + H_2SO_4 \rightarrow NaHSO_4 + HNO_3 \] Thus, product formed is nitric acid.
Step 3: Comparing both reactions.
First reaction produces HCl and second produces HNO\(_3\). These are typical acid displacement reactions involving a stronger acid.
Step 4: Final verification.
No redox change occurs; only proton exchange and acid formation take place.
Step 5: Final conclusion.
Hence, the products formed are HCl and HNO\(_3\).
Final Answer: \[ \boxed{HCl,\ HNO_3} \]
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