Question:
When excess of chlorine is used in the chlorination of methane find the major product obtained.
When excess of chlorine is used in the chlorination of methane find the major product obtained.
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With excess chlorine every hydrogen is replaced and the final product is carbon tetrachloride.
Updated On: Oct 1, 2026
- Chloromethane
- Dichloromethane
- Trichloromethane
- Tetrachloromethane
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
Chlorination of methane is a free radical substitution. It goes step by step: \(\text{CH}_4\to\text{CH}_3\text{Cl}\to\text{CH}_2\text{Cl}_2\to\text{CHCl}_3\to\text{CCl}_4\).
Step 2: Detailed Explanation
Each step replaces one H by Cl. When chlorine is in excess and the reaction continues, substitution does not stop at the first products.
All four hydrogens are replaced, so the major product is \(\text{CCl}_4\) (tetrachloromethane).
Final Answer:
Excess chlorine replaces all four hydrogens, giving tetrachloromethane, option (D). \[ \boxed{\text{CCl}_4\ \text{(D)}} \]
Chlorination of methane is a free radical substitution. It goes step by step: \(\text{CH}_4\to\text{CH}_3\text{Cl}\to\text{CH}_2\text{Cl}_2\to\text{CHCl}_3\to\text{CCl}_4\).
Step 2: Detailed Explanation
Each step replaces one H by Cl. When chlorine is in excess and the reaction continues, substitution does not stop at the first products.
All four hydrogens are replaced, so the major product is \(\text{CCl}_4\) (tetrachloromethane).
Final Answer:
Excess chlorine replaces all four hydrogens, giving tetrachloromethane, option (D). \[ \boxed{\text{CCl}_4\ \text{(D)}} \]
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