Question:
When both the source of sound and observer approach each other with a speed equal to 10% of the speed of sound, then the percentage change in frequency heard by the observer is nearly
When both the source of sound and observer approach each other with a speed equal to 10% of the speed of sound, then the percentage change in frequency heard by the observer is nearly
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When both source and observer move towards each other, Doppler effect frequency shift is calculated by \(\frac{v + v_o}{v - v_s}\).
Updated On: Mar 18, 2026
- 33.3%
- 12.2%
- 22.2%
- 11.1%
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The Correct Option is C
Solution and Explanation
Using Doppler effect formula for both source and observer moving towards each other with speed \(v_s = v_o = 0.1v\), where \(v\) is speed of sound: \[ f' = f \times \frac{v + v_o}{v - v_s} = f \times \frac{v + 0.1v}{v - 0.1v} = f \times \frac{1.1v}{0.9v} = 1.222 f \] Percentage change in frequency: \[ (1.222 - 1) \times 100 = 22.2% \]
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