Question:

A car is approaching a factory siren that has a frequency of 510 Hz. The speed of sound in air is 340 m/s. If the apparent frequency of the sound as heard by the car driver is 600 Hz, then the speed of the car is:

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For Doppler effect with moving observer and stationary source: \(f' = f (v + v_o)/v\). Solve for \(v_o\) when apparent frequency is given.
Updated On: Jun 19, 2026
  • 60 m/s
  • 33.3 m/s
  • 50.5 m/s
  • 80 m/s
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The Correct Option is A

Solution and Explanation

Step 1: Use Doppler effect formula.
\[ f' = f \frac{v + v_o}{v} \quad \text{(source stationary, observer moving towards source)} \] where \(v = 340~\text{m/s}\), \(f = 510~\text{Hz}\), \(f' = 600~\text{Hz}\).

Step 2: Solve for observer speed \(v_o\).

\[ 600 = 510 \frac{340 + v_o}{340} \Rightarrow \frac{600}{510} = \frac{340 + v_o}{340} \] \[ \frac{600}{510} \cdot 340 = 340 + v_o \Rightarrow 400 = 340 + v_o \Rightarrow v_o = 60~\text{m/s} \]

Step 3: Conclusion.

The car is moving at 60 m/s towards the siren.
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