Question:

When a tuning fork of frequency 256 Hz is sounded together with unknown tuning fork, 4 beats are heard in one second. The frequency of the unknown tuning fork can be

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Always use the \(\pm\) sign for unknown frequency problems unless there is extra information (like "frequency increases on waxing" or "decreases on filing").
Updated On: Apr 29, 2026
  • 260 Hz or 252 Hz
  • 258 Hz or 256 Hz
  • 250 Hz or 256 Hz
  • 248 Hz or 255 Hz
  • 257 Hz or 215 Hz
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Beats are produced when two sound waves of slightly different frequencies interfere. The beat frequency (\(n\)) is equal to the absolute difference between the two frequencies.

Step 2: Key Formula or Approach:

\[ n = |f_1 - f_2| \]
or \(f_2 = f_1 \pm n\).

Step 3: Detailed Explanation:

Given:
Known frequency \(f_1 = 256 \text{ Hz}\).
Beat frequency \(n = 4 \text{ beats per second}\).
The frequency of the unknown fork (\(f_2\)) can be either higher or lower than the known frequency by the value of the beat frequency.
Case 1 (Higher): \(f_2 = 256 + 4 = 260 \text{ Hz}\).
Case 2 (Lower): \(f_2 = 256 - 4 = 252 \text{ Hz}\).

Step 4: Final Answer:

The frequency can be 260 Hz or 252 Hz.
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