Question:

When a sonometer wire vibrates in the third overtone, the number of antinodes and nodes formed on the wire are respectively

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Third overtone is the 4th harmonic of a string fixed at both ends.
Updated On: Oct 1, 2026
  • \(4,5\)
  • \(5,4\)
  • \(3,4\)
  • \(4,3\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
A sonometer wire is fixed at both ends, so both ends are nodes. The fundamental has 1 loop, the first overtone has 2 loops, and so on.

Step 2: Third overtone:
Third overtone means the 4th harmonic, so there are 4 loops. Each loop contains one antinode, so antinodes = 4.

Step 3: Count nodes:
With both ends as nodes, nodes = antinodes + 1 = 5.

Step 4: Check:
Option (A): 4 antinodes and 5 nodes. Option (B) swaps the numbers. Options (C) and (D) correspond to the 2nd and 3rd harmonic or other modes.

Final Answer:
The 4th harmonic has 4 antinodes and 5 nodes. \[ \boxed{\text{(A) }4,\ 5} \]
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