Question:
When a person of mass \( m \) climbs up or down a rope with uniform speed \( v \), the tension in the rope is ( \( g \) = acceleration due to gravity)
When a person of mass \( m \) climbs up or down a rope with uniform speed \( v \), the tension in the rope is ( \( g \) = acceleration due to gravity)
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If velocity is constant, net force is zero.
Updated On: Apr 21, 2026
- \( mg \)
- \( m(g+v) \)
- \( m(g-v) \)
- \( mgv \)
- \( m\left(\frac{g}{v}\right) \)
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The Correct Option is A
Solution and Explanation
Concept:
Uniform speed $\Rightarrow$ acceleration = 0.
Step 1: Apply Newton’s law.
\[ T - mg = 0 \]
Step 2: Solve.
\[ T = mg \]
Step 1: Apply Newton’s law.
\[ T - mg = 0 \]
Step 2: Solve.
\[ T = mg \]
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