When a metal spring is elongated within its elastic limit, the spring stores potential energy. However, the nature of the work done depends on whether the spring is being stretched or compressed.
When the spring is stretched, work is done to deform it, and potential energy is stored in the spring. This energy is stored in the form of elastic potential energy. If the spring is subsequently allowed to return to its original length, the stored potential energy is converted back into work. This means that, during the stretching process, the spring is doing work to resist the deformation. Therefore, the correct statement is that work is done by the spring when it is elongated within its elastic limit, as the spring resists the applied force while storing potential energy.
Correct Answer: (A) Work is done by the spring
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Two similar metallic rods of the same length \( l \) and area of cross section \( A \) are joined and maintained at temperatures \( T_1 \) and \( T_2 \) (\( T_1>T_2 \)) at one of their ends as shown in the figure. If their thermal conductivities are \( K \) and \( \frac{K}{2} \) respectively. The temperature at the joining point in the steady state is:

According to equipartition principle, the energy contributed by each translational degree of freedom and rotational degree of freedom at a temperature T are respectively (\( k_B = \text{Boltzmann constant} \)):
Kepler's second law (law of areas) of planetary motion leads to law of conservation of