Question:
When a force of 8 N is applied on a body, its velocity changes from 8 $ms^{-1}$ to $16~ms^{-1}$ in a time of 4 s. The force required to change the velocity of the same body from $16~ms^{-1}$ to $20~ms^{-1}$ in a time of 2 s is}
When a force of 8 N is applied on a body, its velocity changes from 8 $ms^{-1}$ to $16~ms^{-1}$ in a time of 4 s. The force required to change the velocity of the same body from $16~ms^{-1}$ to $20~ms^{-1}$ in a time of 2 s is}
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Always find mass first when force changes under same body conditions.
Updated On: Jun 22, 2026
- 12 N
- 4 N
- 8 N
- 16 N \bigskip
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The Correct Option is A
Solution and Explanation
Concept:
Force depends on mass and acceleration. First we determine the mass of the body using the first condition, then apply it to the second case.
Step 1: Find acceleration in first case.
\[ a_1 = \frac{16 - 8}{4} = 2~m/s^2 \]
Step 2: Find mass using Newton’s second law.
\[ F = ma \Rightarrow 8 = m \cdot 2 \Rightarrow m = 4~kg \]
Step 3: Find acceleration in second case.
\[ a_2 = \frac{20 - 16}{2} = 2~m/s^2 \]
Step 4: Find required force.
\[ F_2 = m a_2 = 4 \cdot 3 = 12~N \] Final Answer: \[ (A)\ 12~N \]
Step 1: Find acceleration in first case.
\[ a_1 = \frac{16 - 8}{4} = 2~m/s^2 \]
Step 2: Find mass using Newton’s second law.
\[ F = ma \Rightarrow 8 = m \cdot 2 \Rightarrow m = 4~kg \]
Step 3: Find acceleration in second case.
\[ a_2 = \frac{20 - 16}{2} = 2~m/s^2 \]
Step 4: Find required force.
\[ F_2 = m a_2 = 4 \cdot 3 = 12~N \] Final Answer: \[ (A)\ 12~N \]
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