Question:
When a coin is tossed twice, which of the following is the probability of getting both tails?
When a coin is tossed twice, which of the following is the probability of getting both tails?
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For two coin tosses, the sample space is \(HH,HT,TH,TT\). Only one outcome gives both tails.
Updated On: Jun 6, 2026
- \(\dfrac{1}{4}\)
- \(\dfrac{3}{4}\)
- \(\dfrac{1}{2}\)
- \(\dfrac{3}{16}\)
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The Correct Option is A
Solution and Explanation
Concept:
Probability is given by: \[ P(E)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \]
Step 1: Write the sample space.
When a coin is tossed twice, the possible outcomes are: \[ HH,\ HT,\ TH,\ TT \] So, total number of outcomes is: \[ 4 \]
Step 2: Identify favourable outcomes.
We need both tails. The favourable outcome is: \[ TT \] So, number of favourable outcomes is: \[ 1 \]
Step 3: Calculate probability. \[ P(\text{both tails})=\frac{1}{4} \] \[ \therefore \text{Correct Answer is (A)} \]
Probability is given by: \[ P(E)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \]
Step 1: Write the sample space.
When a coin is tossed twice, the possible outcomes are: \[ HH,\ HT,\ TH,\ TT \] So, total number of outcomes is: \[ 4 \]
Step 2: Identify favourable outcomes.
We need both tails. The favourable outcome is: \[ TT \] So, number of favourable outcomes is: \[ 1 \]
Step 3: Calculate probability. \[ P(\text{both tails})=\frac{1}{4} \] \[ \therefore \text{Correct Answer is (A)} \]
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