Question:

For the given dataset:
\[ \begin{array}{c|ccc} x & 2 & 3 & 4\\ \hline f(x) & \frac14 & \frac12 & \frac14 \end{array} \] Which of the following is the expected value of \(x\)?

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For discrete probability distribution, expected value is found by multiplying each value of \(x\) with its probability and then adding all products.
Updated On: Jun 6, 2026
  • \(1\)
  • \(2\)
  • \(3\)
  • \(4\)
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The Correct Option is C

Solution and Explanation

Concept:
For a discrete probability distribution, the expected value or mean is: \[ E(X)=\sum xP(x) \]

Step 1: Write the given values.
\[ x=2,3,4 \] and \[ P(2)=\frac14,\quad P(3)=\frac12,\quad P(4)=\frac14 \]

Step 2: Apply the expected value formula.
\[ E(X)=2\left(\frac14\right)+3\left(\frac12\right)+4\left(\frac14\right) \] \[ E(X)=\frac{2}{4}+\frac{3}{2}+\frac{4}{4} \] \[ E(X)=\frac12+\frac32+1 \] \[ E(X)=2+1 \] \[ E(X)=3 \] \[ \therefore \text{Correct Answer is (C)} \]
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