Question:
When 2-methylbutan-2-ol is treated with Lucas reagent (conc. HCl and $\mathrm{ZnCl_2}$) at room temperature, the product obtained is
When 2-methylbutan-2-ol is treated with Lucas reagent (conc. HCl and $\mathrm{ZnCl_2}$) at room temperature, the product obtained is
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Lucas test:
- 3° alcohol $\rightarrow$ immediate turbidity
- Reaction via $\mathrm{S_N1}$
Updated On: Apr 30, 2026
- 2-chlorobutane
- 2-chloro-2-methylbutane
- 1-chlorobutane
- 1-chloropentane
- 2-chloro-2-methylbutene
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The Correct Option is B
Solution and Explanation
Concept:
Lucas reagent ($\mathrm{conc.\ HCl + ZnCl_2}$) converts alcohols to alkyl chlorides:
• Tertiary alcohols react immediately via $\mathrm{S_N1}$ mechanism
Step 1: Identify type of alcohol.
2-methylbutan-2-ol is a tertiary alcohol.
Step 2: Reaction mechanism.
\[ \mathrm{(CH_3)_2C(OH)CH_2CH_3 \xrightarrow{HCl/ZnCl_2} (CH_3)_2CClCH_2CH_3} \]
Step 3: Product formed.
\[ \text{2-chloro-2-methylbutane} \]
• Tertiary alcohols react immediately via $\mathrm{S_N1}$ mechanism
Step 1: Identify type of alcohol.
2-methylbutan-2-ol is a tertiary alcohol.
Step 2: Reaction mechanism.
\[ \mathrm{(CH_3)_2C(OH)CH_2CH_3 \xrightarrow{HCl/ZnCl_2} (CH_3)_2CClCH_2CH_3} \]
Step 3: Product formed.
\[ \text{2-chloro-2-methylbutane} \]
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