The correct option is (C): 66 cm/sec
Explanation:
Distance covered by big wheel in 1 revolution = \(2πr\)
= \(2\times\frac{22}{7}\times7=44 cm\)
and by small wheel = 22 cm
Since, distance ox speed
Let speed of small wheel = \(x\frac{cm}{s}\), = Speed of big wheel = 2x cm/s
Also, relative speed of both wheels = \(\frac{1980}{10}\)=198 cm
\(x\) + 2\(\)\(x\) = 198
\(x\)=\(\frac{198}{3}\)=66 cm/s