Question:
What will happen when D(+)-glucose is treated with methanolic HCl followed by Tollens’ reagent?
What will happen when D(+)-glucose is treated with methanolic HCl followed by Tollens’ reagent?
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Glycoside formation:
• Blocks the reducing end
• Makes sugars non-reducing
Updated On: Mar 19, 2026
- A black precipitate will be formed
- A red precipitate will be formed
- A green colour will appear
- No characteristic colour or precipitate will be formed
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Methanolic HCl converts glucose into methyl glucoside by acetal formation.
Step 2: In methyl glucoside, the free aldehyde group is blocked.
Step 3: Tollens’ reagent gives a positive test only with free aldehyde groups. ⟹ No reaction with Tollens’ reagent
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